Prove the following:
`"sin" alpha+"sin" beta+"sin" gamma-"sin"(alpha+beta+gamma)=4"sin"(alpha+beta)/(2)"sin"(beta+gamma)/(2)"sin"(gamma+alpha)/(2)`

Prove that: sin alpha+sin beta+sin gamma-sin(alpha+beta+gamma)=4sin((alpha+beta)/(2))sin((beta+gamma)/(2))sin((gamma+alpha)/(2))

Prove that: sin alpha+sin beta+sin gamma-sin(alpha+beta+gamma)=4sin((alpha+beta)/(2))*sin((beta+gamma)/(2))*sin((gamma+alpha)/(2))

cos alpha sin (beta-gamma) + cos beta sin (gamma-alpha) + cos gamma sin (alpha-beta) =

Prove that: |(sinalpha, cosalpha, 1),(sinbeta, cosbeta, 1),(singamma, cosgamma, 1)|=sin(alpha-beta)+sin(beta-gamma)+sin(gamma-alpha)

If 2 sin alphacos beta sin gamma=sinbeta sin(alpha+gamma),then tan alpha,tan beta and gamma are in

sin (beta+ gamma- alpha) + sin (gamma+ alpha - beta) + sin (alpha + beta- gamma)- sin (alpha + beta + gamma)=

prove that | (sin alpha, sin beta, sin gamma), (cos alpha, cos beta, cos gamma), (sin 2alpha, sin 2beta, sin 2gamma) | = 4sin (1/2) (beta-gamma) * sin (1/2) (gamma-alpha) * sin (1/2) (alpha-beta) xx {sin (beta + gamma) + sin (gamma + alpha) + sin (alpha + beta)}.

Let alpha,beta and gamma are the angles of a right angle triangle,then the value of sin alpha*sin beta*sin(alpha-beta)+sin beta*sin gamma*sin(beta-gamma)+sin gamma*sin alpha*sin(gamma-beta)+sin(beta-gamma)*sin(gamma-gamma)*sin(gamma-

If cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma then x^(sin(2 alpha-beta-gamma)*x^(sin(2 beta-gamma-alpha)))*x ^(sin(2 gamma-alpha-beta)) is

cos (alpha + beta) cos gamma-cos (beta + gamma) cos alpha = sin beta sin (gamma-alpha)