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Find "sin" 7(1^(@))/(2),cos 7(1^(@))/(2)...

Find `"sin" 7(1^(@))/(2),cos 7(1^(@))/(2)` and `"tan" 11(1^(@))/(4)`.

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To solve the problem of finding \( \sin 7\frac{1}{2}^\circ \), \( \cos 7\frac{1}{2}^\circ \), and \( \tan 11\frac{1}{4}^\circ \), we will break it down step by step. ### Step 1: Convert Mixed Fractions to Improper Fractions First, we convert the mixed fractions into improper fractions. For \( 7\frac{1}{2}^\circ \): \[ 7\frac{1}{2} = 7 + \frac{1}{2} = \frac{14}{2} + \frac{1}{2} = \frac{15}{2}^\circ \] For \( 11\frac{1}{4}^\circ \): \[ 11\frac{1}{4} = 11 + \frac{1}{4} = \frac{44}{4} + \frac{1}{4} = \frac{45}{4}^\circ \] ### Step 2: Finding \( \sin 7\frac{1}{2}^\circ \) Now we need to find \( \sin \frac{15}{2}^\circ \). Using the sine angle addition formula, we can express \( \sin \frac{15}{2}^\circ \) as: \[ \sin \frac{15}{2}^\circ = \sin(7^\circ + \frac{1}{2}^\circ) \] ### Step 3: Applying the Sine Addition Formula Using the sine addition formula: \[ \sin(A + B) = \sin A \cos B + \cos A \sin B \] Let \( A = 7^\circ \) and \( B = \frac{1}{2}^\circ \): \[ \sin \frac{15}{2}^\circ = \sin 7^\circ \cos \frac{1}{2}^\circ + \cos 7^\circ \sin \frac{1}{2}^\circ \] ### Step 4: Finding \( \cos 7\frac{1}{2}^\circ \) Similarly, we can find \( \cos \frac{15}{2}^\circ \): \[ \cos \frac{15}{2}^\circ = \cos(7^\circ + \frac{1}{2}^\circ) \] Using the cosine addition formula: \[ \cos(A + B) = \cos A \cos B - \sin A \sin B \] So, \[ \cos \frac{15}{2}^\circ = \cos 7^\circ \cos \frac{1}{2}^\circ - \sin 7^\circ \sin \frac{1}{2}^\circ \] ### Step 5: Finding \( \tan 11\frac{1}{4}^\circ \) Now we find \( \tan \frac{45}{4}^\circ \): \[ \tan \frac{45}{4}^\circ = \tan(11^\circ + \frac{1}{4}^\circ) \] Using the tangent addition formula: \[ \tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \tan B} \] Let \( A = 11^\circ \) and \( B = \frac{1}{4}^\circ \): \[ \tan \frac{45}{4}^\circ = \frac{\tan 11^\circ + \tan \frac{1}{4}^\circ}{1 - \tan 11^\circ \tan \frac{1}{4}^\circ} \] ### Step 6: Final Values Now we can substitute the known values of \( \sin 7^\circ \), \( \cos 7^\circ \), \( \sin \frac{1}{2}^\circ \), \( \cos \frac{1}{2}^\circ \), \( \tan 11^\circ \), and \( \tan \frac{1}{4}^\circ \) to get the final results for \( \sin 7\frac{1}{2}^\circ \), \( \cos 7\frac{1}{2}^\circ \), and \( \tan 11\frac{1}{4}^\circ \).
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MODERN PUBLICATION-TRIGONOMETRY-Exercise 3(g)Long Answer type Question-I
  1. Prove that: "sin" 4A=4 sin A cos^(3)A-4 cos A "sin"^(3)A.

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  2. If cos theta=(1)/(2)(alpha+(1)/(alpha)),prove that: (i) 2 cos 2thet...

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  3. If x+(1)/(x)=2costheta, then find the valueof x^(3)+(1)/(x^(3)).

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  4. Prove that: (i) cos A cos(60^(@)-A)cos (60^(@)+A)=(1)/(4)cos 3A ...

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  5. cos^2alpha+cos^2(alpha+120^0)+cos^2(alpha-120^0)=3/2

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  6. If tan^2theta=1+2tan^2phi then show that cos2theta+sin^2phi=0

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  7. Find sin x/2 ,cos x/2 and t a n x/2 of the following : s in" "x" "=1/...

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  8. (i) If "tan""(x)/(2)=(m)/(n),prove that m sin x+n cos x=n. (ii) If...

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  9. Prove that (cos^(3)theta-cos 3theta)/(cos theta)+("sin"^(3)theta+"sin"...

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  10. Evaluate: (i) "sin""(3pi)/(8) (ii) "sin""(5pi)/(24) (iii) "tan""(pi...

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  11. Prove that: s in^4pi/8+s in^4(3pi)/8+s in^4(5pi)/8+s in^4(7pi)/8=3/2

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  12. Prove that: (i) "sin"^(2)6x-"sin"^(2)4x="sin" 2x sin 10x (ii) c...

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  13. Find "sin" 7(1^(@))/(2),cos 7(1^(@))/(2) and "tan" 11(1^(@))/(4).

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  14. Prove that: "tan" 142(1^(@))/(2)=2+sqrt2-sqrt3-sqrt6.

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  15. Prove that cotxcot2x-cot2xcot3x-cot3xcotx=1

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  16. Prove that: (i) sin 3x+"sin" 2x-"sin" x =4 sin x cos((x)/(2))cos...

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  17. Prove that cos^2x+cos^2(x+pi/3)+cos^2(x-pi/3)=3/2

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  18. If cos theta=(cos phi-e)/(1-e cos phi),show that: "tan"(theta)/(2)...

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