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If "tan" theta=-(4)/(5), then "sin" thet...

If `"tan" theta=-(4)/(5)`, then `"sin" theta` is:

A

`-(4)/(5)` but not `(4)/(5)`

B

`-(4)/(5)` or `(4)/(5)`

C

`(4)/(5)` but not `-(4)/(5)`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \(\sin \theta\) given that \(\tan \theta = -\frac{4}{5}\), we can follow these steps: ### Step 1: Identify the Quadrant Since \(\tan \theta\) is negative, \(\theta\) must be in either the second or the fourth quadrant. In the second quadrant, \(\sin \theta\) is positive, while in the fourth quadrant, \(\sin \theta\) is negative. ### Step 2: Set Up the Right Triangle Using the definition of tangent, we can set up a right triangle where: - The opposite side (perpendicular) is 4 (since \(\tan \theta = \frac{\text{opposite}}{\text{adjacent}} = -\frac{4}{5}\)). - The adjacent side (base) is 5. ### Step 3: Calculate the Hypotenuse Using the Pythagorean theorem: \[ \text{Hypotenuse} (H) = \sqrt{(\text{opposite})^2 + (\text{adjacent})^2} = \sqrt{4^2 + 5^2} = \sqrt{16 + 25} = \sqrt{41} \] ### Step 4: Calculate \(\sin \theta\) Now, we can find \(\sin \theta\): \[ \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{4}{\sqrt{41}} \] ### Step 5: Determine the Sign of \(\sin \theta\) Since \(\tan \theta\) is negative and we are in the second quadrant, \(\sin \theta\) will be positive: \[ \sin \theta = \frac{4}{\sqrt{41}} \] ### Final Answer Thus, the value of \(\sin \theta\) is: \[ \sin \theta = \frac{4}{\sqrt{41}} \]
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Knowledge Check

  • If tan theta = - (4)/(3) , then sin theta is

    A
    `-4//5` but not 4/5
    B
    `-4//5` or 4/5
    C
    4/5 but not -4/5
    D
    None of these
  • If tan theta = (4)/(3) , then 3sin theta - 4 cos theta =

    A
    0
    B
    1
    C
    `(4)/(5)`
    D
    `(3)/(5)`
  • If tan theta = - 4 //3 , then sin theta is

    A
    `- 4//5` but not `4//5`
    B
    `-4//5` or `4//5`
    C
    `4//5` but not `- 4//5`
    D
    none of these
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