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The general solution of the equation 2 s...

The general solution of the equation `2 sin x+1=0` is:

A

`x=2npi pm(pi)/(6),n epsilonZ`

B

`x=npi pm(pi)/(6),n epsilonZ`

C

`x=2npi+(-1)^(n)(pi)/(6),n epsilonZ`

D

`x=2npi-(-1)^(n+1)(pi)/(6),n epsilonZ`

Text Solution

Verified by Experts

The correct Answer is:
d
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