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sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2...

`sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2`

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sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)-(1)/(2)(pi)/(4)=-(1)/(2)

Find the value of the sin^(2)((pi)/(6))+cos^(2)((pi)/(3))-tan^(2)((pi)/(4))

Knowledge Check

  • What is sin^2(3pi)+cos^2(4pi)+tan^2(5pi) equal to?

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    0
    B
    1
    C
    2
    D
    3

  • What is sin^(2)(3pi)+cos^(2)(4pi)+tan^(2)(5pi) equal to ?

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    0
    B
    1
    C
    2
    D
    3

  • If [[sin((pi)/(2)), cos((pi)/(3))], [2tan((pi)/(4)), 2k]] is not invertible, then k=

    A
    `2`
    B
    `(1)/(2)`
    C
    `1`
    D
    `3`

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