If `sin(theta+alpha)=aa n dsin(theta+beta)=b ,` prove that `cos2(alpha-beta)-4a bcos(alpha-beta)=1-2a^2-2b^2`

If sin(theta+alpha)=a and sin(theta+beta)=b, prove that cos2(alpha-beta)-4ab cos(alpha-beta)=1-2a^(2)-2b^(2)

s(theta-alpha)=a and cos(theta-beta)=b, then sin^(2)(alpha-beta)+2ab cos(alpha-beta)=

If cos(theta-alpha)=a,sin(theta-beta)=b, prove that a^(2)-2ab sin(alpha-beta)+b^(2)=cos^(2)(alpha-beta)

If cos(theta-alpha)=a and cos(theta-beta)=b then the value of sin^(2)(alpha-beta)+2ab cos(alpha-beta)

If cos (theta -alpha) =a, sin (theta - beta) =b, then cos ^(2) (alpha - beta) + 2 ab sin (alpha - beta) is equal to

If cos(theta-alpha)=p and sin(theta+beta)=q show that p^(2)+q^(2)-2pq sin(alpha+beta)=cos^(2)(alpha+beta)

It is given that cos(theta-alpha)=a, cos(theta-beta)=b What is sin^(2)(alpha-beta)+2abcos(alpha-beta) equal to ?

If cos (theta - alpha) = a and sin(theta - beta) = b (0 lt theta - alpha, theta - beta lt pi//2) , then prove that cos^(2) (alpha - beta) + 2ab sin (alpha - beta) = a^(2) + b^(2)