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How many of the natural numbers can be f...

How many of the natural numbers can be formed from the digits 2, 3, 5, 7, 9 ? How many of them are odd?

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To solve the problem of how many natural numbers can be formed from the digits 2, 3, 5, 7, and 9, we will consider two cases: when digits can repeat and when digits cannot repeat. ### Case 1: Digits Cannot Repeat 1. **1-Digit Numbers**: - The available digits are 2, 3, 5, 7, and 9. - Total options = 5 (2, 3, 5, 7, 9). 2. **2-Digit Numbers**: - For the first digit, we have 5 options (2, 3, 5, 7, 9). - For the second digit, since digits cannot repeat, we have 4 options left. - Total = 5 × 4 = 20. 3. **3-Digit Numbers**: - For the first digit, we have 5 options. - For the second digit, we have 4 options. - For the third digit, we have 3 options left. - Total = 5 × 4 × 3 = 60. 4. **4-Digit Numbers**: - For the first digit, we have 5 options. - For the second digit, we have 4 options. - For the third digit, we have 3 options. - For the fourth digit, we have 2 options left. - Total = 5 × 4 × 3 × 2 = 120. 5. **5-Digit Numbers**: - For the first digit, we have 5 options. - For the second digit, we have 4 options. - For the third digit, we have 3 options. - For the fourth digit, we have 2 options. - For the fifth digit, we have 1 option left. - Total = 5 × 4 × 3 × 2 × 1 = 120. 6. **Total Natural Numbers (Digits Cannot Repeat)**: - Total = 5 (1-digit) + 20 (2-digit) + 60 (3-digit) + 120 (4-digit) + 120 (5-digit) - Total = 5 + 20 + 60 + 120 + 120 = 325. ### Case 2: Digits Can Repeat 1. **1-Digit Numbers**: - The available digits are still 2, 3, 5, 7, and 9. - Total options = 5. 2. **2-Digit Numbers**: - For the first digit, we have 5 options. - For the second digit, since digits can repeat, we again have 5 options. - Total = 5 × 5 = 25. 3. **3-Digit Numbers**: - For the first digit, we have 5 options. - For the second digit, we have 5 options. - For the third digit, we have 5 options. - Total = 5 × 5 × 5 = 125. 4. **4-Digit Numbers**: - For each digit, we have 5 options. - Total = 5 × 5 × 5 × 5 = 625. 5. **5-Digit Numbers**: - For each digit, we have 5 options. - Total = 5 × 5 × 5 × 5 × 5 = 3125. 6. **Total Natural Numbers (Digits Can Repeat)**: - Total = 5 (1-digit) + 25 (2-digit) + 125 (3-digit) + 625 (4-digit) + 3125 (5-digit) - Total = 5 + 25 + 125 + 625 + 3125 = 3905. ### Summary of Results - Total natural numbers formed when digits cannot repeat: **325**. - Total natural numbers formed when digits can repeat: **3905**.
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MODERN PUBLICATION-PERMUTATIONS AND COMBINATIONS -EXERCISE 7 (d) Long Answer Type Questions - I
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