Home
Class 11
MATHS
If ""^(n)C(a)= ""^(n)C(b)' then find n...

If `""^(n)C_(a)= ""^(n)C_(b)`' then find n.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem where \( \binom{n}{a} = \binom{n}{b} \), we will use the properties of combinations. ### Step-by-step Solution: 1. **Understanding the Property of Combinations**: We know that \( \binom{n}{r} = \binom{n}{n-r} \). This means that the number of ways to choose \( r \) items from \( n \) is the same as choosing \( n-r \) items from \( n \). 2. **Setting Up the Equation**: Given that \( \binom{n}{a} = \binom{n}{b} \), we can apply the property mentioned above. This implies: \[ \binom{n}{a} = \binom{n}{n-b} \] 3. **Equating the Indices**: From the equality \( \binom{n}{a} = \binom{n}{n-b} \), we can conclude that: \[ a = n - b \quad \text{or} \quad b = n - a \] 4. **Finding the Value of \( n \)**: Rearranging the equation \( a + b = n \), we find: \[ n = a + b \] 5. **Conclusion**: Therefore, the value of \( n \) is given by: \[ n = a + b \] ### Final Answer: The value of \( n \) is \( a + b \).
Promotional Banner

Topper's Solved these Questions

  • PERMUTATIONS AND COMBINATIONS

    MODERN PUBLICATION|Exercise COMPETITION FILE (JEE MAIN)|11 Videos
  • PERMUTATIONS AND COMBINATIONS

    MODERN PUBLICATION|Exercise CHAPTER TEST|12 Videos
  • PERMUTATIONS AND COMBINATIONS

    MODERN PUBLICATION|Exercise Revision Exercise|22 Videos
  • MOCK TEST

    MODERN PUBLICATION|Exercise SECTION - D|5 Videos
  • PROBABILITY

    MODERN PUBLICATION|Exercise CHAPTER TEST|12 Videos

Similar Questions

Explore conceptually related problems

If ""^(n)C_(10)=""^(n)C_(13) , then find the value of ""^(n)C_(2)

(i) If ""^(n)C_(8)= ""^(n)C_(2) , find ""^(n)C_(2) . (ii) If ""^(n)C_(10)= ""^(n)C_(12) , determine n and hence ""^(n)C_(5) . (iii) If ""^(n)C_(9)= ""^(n)C_(8) , find ""^(n)C_(17) .

If .^(n)C_(5) = .^(n)C_(7) , then find .^(n)P_(3)

If ""^(n)C_(7)=""^(n)C_(5) , find ""^(n)C_(4) .

If .^(n)C_(8)=.^(n)C_(6) , then find .^(n)C_(2) .

If ""^(n)C_(10)= ""^(n)C_(9) , find ""^(n)C_(19) .

If ^(n)C_(8)=^(n)C_(6), then find ^(n)C_(2)

If ""^(n)C_(8)= ""^(n)C_(9) , find the value of n.