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A man X has 7 friends, 4 of them are ...

A man `X` has `7` friends, `4` of them are ladies and `3` are men. His wife `Y` also has `7` friends, `3` of them are ladies and 4 are men. Assume `X` and `Y` have no common friends. Then the total number of ways in which `X` and `Y` together can throw a party inviting 3 ladies and 3 men, so that 3 friends of each of `X` and `Y` are in the party, is :

A

468

B

469

C

484

D

485

Text Solution

Verified by Experts

The correct Answer is:
D
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