In each of the following differential equations, indicate its degree, wherever possible. Also, give the order of each of them
`(y'')^(2)+(y')^(3)+sin y = 0`

Answer

To solve the problem, we need to determine the order and degree of the given differential equation:

\[ (y'')^2 + (y')^3 + \sin y = 0 \]

### Step 1: Identify the highest derivative
The first step is to identify the highest derivative present in the equation. In this case, we have:

- \(y''\) (the second derivative of \(y\))
- \(y'\) (the first derivative of \(y\))

The highest derivative here is \(y''\).

### Step 2: Determine the order
The order of a differential equation is defined as the highest order of derivative present in the equation. Since the highest derivative is \(y''\), which is a second derivative, the order of the equation is:

\[ \text{Order} = 2 \]

### Step 3: Determine the degree
The degree of a differential equation is defined as the power of the highest derivative when the equation is a polynomial in derivatives. In this equation, the highest derivative \(y''\) appears in the term \((y'')^2\). The power of this highest derivative is 2.

Thus, the degree of the equation is:

\[ \text{Degree} = 2 \]

### Final Answer
- **Order**: 2
- **Degree**: 2