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Find the order and degree, if defined, o...

Find the order and degree, if defined, of the following differential equation :
`xy (d^(2)y)/(dx^(2))+x((dy)/(dx))^(2)-y(dy)/(dx)=0`

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To find the order and degree of the given differential equation: \[ xy \frac{d^2y}{dx^2} + x \left( \frac{dy}{dx} \right)^2 - y \frac{dy}{dx} = 0 \] we will follow these steps: ### Step 1: Identify the highest order derivative The first step is to identify the highest order derivative present in the equation. In the given equation, we have: - \( \frac{d^2y}{dx^2} \) (the second derivative) - \( \frac{dy}{dx} \) (the first derivative) The highest order derivative is \( \frac{d^2y}{dx^2} \). ### Step 2: Determine the order The order of a differential equation is defined as the highest order of the derivative present in the equation. Since the highest order derivative is \( \frac{d^2y}{dx^2} \), the order of the differential equation is: **Order = 2** ### Step 3: Determine the degree The degree of a differential equation is defined as the power of the highest order derivative when the equation is a polynomial in derivatives. In our equation, the term involving the highest order derivative \( \frac{d^2y}{dx^2} \) appears as: \[ xy \frac{d^2y}{dx^2} \] Here, \( \frac{d^2y}{dx^2} \) is raised to the power of 1. Therefore, the degree of the differential equation is: **Degree = 1** ### Final Answer - **Order = 2** - **Degree = 1**
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MODERN PUBLICATION-DIFFERENTIAL EQUATIONS-EXERCISE 9 (a) Short Answer Type Questions
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