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Find the order and degree, if defined, o...

Find the order and degree, if defined, of the following differential equation :
`(d^(2)y)/(dx^(2))=(2y^(3)+((dy)/(dx))^(4))/(sqrt((d^(2)y)/(dx^2)))`

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To find the order and degree of the given differential equation: \[ \frac{d^2y}{dx^2} = \frac{2y^3 + \left(\frac{dy}{dx}\right)^4}{\sqrt{\frac{d^2y}{dx^2}}} \] we will follow these steps: ### Step 1: Identify the highest derivative The highest derivative present in the equation is \(\frac{d^2y}{dx^2}\). ### Step 2: Determine the order The order of a differential equation is defined as the highest order of derivative present. In this case, the highest derivative is \(\frac{d^2y}{dx^2}\), which is a second derivative. Therefore, the order of the differential equation is: \[ \text{Order} = 2 \] ### Step 3: Rearrange the equation To find the degree, we need to express the equation in a polynomial form. The given equation has a square root in the denominator, which complicates finding the degree directly. We can eliminate the square root by squaring both sides of the equation. Squaring both sides gives: \[ \left(\frac{d^2y}{dx^2}\right)^2 = \left(2y^3 + \left(\frac{dy}{dx}\right)^4\right) \] ### Step 4: Rearranging the equation Now we can rearrange the equation: \[ \left(\frac{d^2y}{dx^2}\right)^2 - \left(2y^3 + \left(\frac{dy}{dx}\right)^4\right) = 0 \] ### Step 5: Identify the highest power of the highest derivative In the rearranged equation, the highest derivative is \(\frac{d^2y}{dx^2}\), and its highest power is 2 (from \(\left(\frac{d^2y}{dx^2}\right)^2\)). ### Step 6: Determine the degree The degree of a differential equation is defined as the highest power of the highest order derivative when the equation is expressed as a polynomial in derivatives. Since the highest derivative \(\frac{d^2y}{dx^2}\) has a power of 2, the degree of the differential equation is: \[ \text{Degree} = 2 \] ### Final Answer Thus, the order and degree of the given differential equation are: - **Order:** 2 - **Degree:** 2
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MODERN PUBLICATION-DIFFERENTIAL EQUATIONS-EXERCISE 9 (a) Short Answer Type Questions
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