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At any point P(x,y) of a curve, the slop...

At any point `P(x,y)` of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact `P` to the point `(-4,-3)` Find the equation of the curve given that it passes through the point `(-2, 1)`

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The correct Answer is:
`x^(2)+8x-y+13=0`
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