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The rate of increase in the number of bacteria in a certain bacteria culture is proportional to the number present. Given the number triples in 5 hrs., find how many bacteria will be present after 10 hours. Also find the time necessary for the number of bacteria to be 10 times the number of initial present. [Given `(log)_e3=1. 0986 ,\ e^(2. 1972)=9` ]

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The correct Answer is:
9 times, `5 (log 10 )/(log 3) ` hours.
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