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Two adjacent sides of a parallelogram AB...

Two adjacent sides of a parallelogram ABCD are given by :
`vec(AB) = 2hati + 10 hatj+ 11 hatk and vec(AD) =- hati + 2 hatj + 2 hatk.` The side AD is rotated by an acute angle `alpha ` in the plane of the parallelogram so that AD becomes AD'. If AD' makes a right angle with the side AB, then the cosine of the angle `alpha` is given by

A

`8/9`

B

`(sqrt17)/(9)`

C

`1/9`

D

`(4 sqrt5)/(9).`

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The correct Answer is:
B
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