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Let omega be a complex cube a root of u...

Let `omega ` be a complex cube a root of unity with `omega != 1 ` . A fair die is thrown three times . If `r_(1),r_(2) and r_(3)` are the numbers obtained on the die , then the probability that `omega^(r_(1))+omega^(r_(2))+omega^(r_(3))= 0 ` is :

A

`1/18`

B

`1/9`

C

`2/9`

D

`1/36`

Text Solution

Verified by Experts

The correct Answer is:
C
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