An `LCR` circuit has `L = 10 mH`. `R = 3` ohm and `C = 1 mu F` connected in series to a source is `15 cos omega t` volt. What is average power dissipated per cycle at a frequency that is `10%` lower than the resonant requency?

An LCR circuit has L = 10 mH, R = 3 Omega and C = 1 mu F connected in series to a source of 15cos omega t .volt. Calculate the current ampliuted and the average power dissipated per cycle at a frequency 10% lower than the resonance frequency.

An LCR circuit has L = 10 mH, R = 3 Omega and C = 1 mu F connected in series to a source of 15 copy cos omega t .volt. Calculate the current ampliuted and the average power dissipated per cycle at a frequency 10% lower than the resonance frequency.

An LCR circuit has L = 10 mL, R = 3 Omega , and C = 1 mu F connected in series to a source of 15 cos omega t volt. The current amplitude at a frequency that is 10% lower then the resonant frequency is

An LCR circuit has L = 10 mH, R = 3 Omega and C = 1 mu F and is connected in series to a source of (15 cos omega t) volt. Calculate the current amplitude at a frequency 10 % lower than the resonance frequency of the circuit.

An LCR circuit has L = 10 mH, R = 3 Omega and C = 1 mu F and is connected in series to a source of (20 sin omega t) volt. Calculate the current amplitude at a frequency 20 % lower than the resonance frequency of the circuit.

An LCR circuit has L=10 mH,R=150 Omega and C=1 muF connacted in series to a source of 150sqrt2 cos omegat volt. At a frequency that is 50% of the resonant frequency.calculate the average power (in watt) dissipated per cycle.

An LCR circuit has L=10 mH,R=150 Omega and C=1 muF connacted in series to a source of 150sqrt2 cos omegat volt. At a frequency that is 50% of the resonant frequency.calculate the average power (in watt) dissipated per cycle.