Consider a variable force `F=(3x+5)N` acting on a body and if it is displaced from `x=2m` to `x=4m`, calculate the work done by this force.

The force F= (2 + 4x^2 + 2x^3) N acting on a body displaces from zero to 5m. Calcilate the total work done by the force .

A force of 3x^(2)-2x+5 acts on a body of mass 5 kg and displaces it from x=0 to x=4 m. What is the work done by the force?

A position dependent force F=7-2x+3x^(2) acts on a small body of mass 2 kg and displaced it from x=0 to x=5m . Calculate the work done in joule.

A position dependent force F=7-2x+3x^(2) acts on a small body of mass 2 kg and displaced it from x=0 to x=5m . Calculate the work done in joule.

A force of (4x^(2)+3x)N acts on a particle which displaces it from x=2m to x = 3m . The work done by the force is

A force of (4x^(2)+3x)N acts on a particle which displaces it from x=2m to x=3m. The work done by the force is