Home
Class 12
MATHS
The graph of the function y=f(x) passin...

The graph of the function `y=f(x)` passing through the point (0,1) and satisfying the differential equation `(dy)/(dx)+ycosx=cosx` is such that (a) it is a constant function. (b) it is periodic (c) it is neither an even nor an odd function. (d) it is continuous and differentiable for all ` f(x )`

Promotional Banner

Similar Questions

Explore conceptually related problems

The graph of the function y = f(x) passing through the point (0, 1) and satisfying the differential equation (dy)/(dx) + y cos x = cos x is such that

The graph of the function y = f(x) passing through the point (0, 1) and satisfying the differential equation (dy)/(dx) + y cos x = cos x is such that

The graph of the founction y=f(x) passing through the point (0,1) and satisfying the differntial equation (dy)/(dx)+ycos=cosx is such that

The graph of the founction y=f(x) passing through the point (0,1) and satisfying the differntial equation (dy)/(dx)+ycos=cosx is such that

The graph of the function y=f(x) passing through the point (0,1) and satisfying the differential equation (dy)/(dx)+y cos x=cos x is such that (a) it is a constant function.(b) it is periodic ( ) it is neither an even nor an odd function.(d) it is neither an even nor an odd for all f(x)

The graph of the function y=f(x) passing through the point (0,1) and satisfying the differential equation (dy)/(dx)+ycosx=cosx is such that (a) it is a differential function for all x E R. (b)it is continuous for all x E R. (c) it is periodic . (d) it is passing through(pi,1)

If y=f(x) passing through (1,2) satisfies are differential equation y(1+xy)dx-x dy=0, then

The function f(x)=log(x+sqrt(x^(2)+1)) , is (a) an even function (b) an odd function (c ) a periodic function (d) Neither an even nor an odd function.

A function y=f(x) satisfies the differential equation (dy)/(dx)+x^(2)y+2x=0,f(1)=1 then the value of f(1) is-

If the function y=e^(4x)+2e^(-x) satisfies the differential equation (d^(3)y)/(dx^(3))+A(dy)/(dx)+By=0 , then (A,B)-=