If the probability density function of a random variable X is `f(x)=x/2` in `0 le x le 2`, then `P(X gt 1.5 | X gt 1)` is equal to

The probability density function of a random variable X is f(x) = k(x-1)^2 , 1 le x le 2 . The value of the constant K is

The probability of a random variable X is given below Determine P (X le 2) and P (X gt 2)

The probability of a random variable X is given below Determine P (X le 2) and P (X gt 2)

The probability density function of the random variable X is given by f(x)={{:(16xe^(-4x), "for " x gt 0), (0, "for " x le 0):} find the mean and variance of X

The probability of a random variable X is given below Find P (X le 2 ) + P (X gt 2)

The probability of a random variable X is given below Find P (X le 2 ) + P (X gt 2)

If the p.d.f of a random variable X is f(x)={(0.5x, 0lexle2), (0, "otherwise"):} Then the value of P(0.5 le X le 1.5) is

The probability distribution of a random variable X is given below: (i) Determine the value of k. (ii) Determine P(X le 2) and P(X gt 2) (ii) Find P(X le 2) +P(X gt 2) .

If the p.d.f of a random variable X is F(x)={(0.5x, 0lexle2), (0, "otherwise"):} Then the value of P(0.5 le X le 1.5) is