Three mole of electrons are passed through three solutions in succession containing `AgNO_(3), CuSO_(4)` and `AuCl_(3)` respectively. The ratio of amounts of cations reduced at cathode will be :

Three moles of electrons are passed through three solutions in succession containing AgNO_(3),CuSO_(4) and AuCl_(3) respectively. The molar ratio of amounts of cations reduced at cathode will be

Three moles of electrons are passed through three solutions in succession containing AgNO_(3),CuSO_(4) and AuCI_(3) respectively. The molar ratio of amounts of cations reduced at cathode will be:-

Three moles of electrons are passed through three solutions in succession containing AgNO_(3),CuSO_(4) and AuCI_(3) respectively. The molar ratio of amounts of cations reduced at cathode will be:-

Three moles of electrons are passed through three solutions in succession containing AgNO_3 , CuSO_4 and AuCL_3 respectively the molar ratio of amounts of cations reduced at cathode will be

If three Faradays of electricity is passed through the solutions of AgNO_(3), CuSO_(4) and AuCl_(3), the molar ratio of the cations deposited at the cathodes will be :

Exactly 0.2 mole electrons are passed through two electrolytic cells in series containing CuSO_(4) and ZnSO_(4) respectively. How many grams of each metal will be deposited on the respective cathodes in the two cells ?