यदि बिन्दु `(at^(2),2at)` तथा `(at_(1)^(2),2at_(1))` परवलय `y^(2)=4ax` की नाभीय जीवा के सिरे है, तो सिद्ध कीजिए की `tt_(1)=-1.`

The points (at_(1)^(2),2at_(1)),(at_(2)^(2),2at_(2)) and (a,0) will be collinear,if

Let P(at_(1)^(2),2at_(1)) and Q(at_(2)^(@),2at_(2)) are two points on the parabola y^(2)=4ax Then,the equation of chord is y(t_(1)+t_(2))=2x+2at_(1)t_(2)

" If the normal at the point " t_(1)(at_(1)^(2),2at_(1)) " on " y^(2)=4ax " meets the parabola again at the point " t_(2) " ,then " t_(1)t_(2) =

The tangents at the points (at_(1)^(2),2at_(1)) , (at_(2)^(2),2at_(2)) on the parabola y^(2)=4ax are al right angles if

If P(at_(1)^(2),2at_(1)) and Q(at_(2)^(2),2at_(2)) are the ends of focal chord of the parabola y^(2)=4ax then t_(1)t_(2)

If P(at_(1)^(2), 2at_(1))" and Q(at_(2)^(2), 2at_(2)) are two points on the parabola at y^(2)=4ax , then that area of the triangle formed by the tangents at P and Q and the chord PQ, is

If P(at_(1)^(2), 2at_(1))" and Q(at_(2)^(2), 2at_(2)) are two points on the parabola at y^(2)=4ax , then that area of the triangle formed by the tangents at P and Q and the chord PQ, is

If the normal at (at_(1)^(2), 2at_(1))" to " y^(2) =4ax intersect the parabola at (at_(2)^(2), 2at_(2)) , prove that, t_(1)+t_(2)+(2)/(t_1)=0(t_(1) ne 0)

Show that the points (at_(1)^(2),2at_(1)) , (at_(2)^(2),2at_(2)) and (a,0) are collinear if t_1t_2 =-1 .