In `Delta ABC` ,equation of BC is `x-y=0` if the circum center and orthocenter are`(2,3),(5,8)` then the circumradius is

In DeltaABC equation of BC is x-y=0. If the circumcentre and othcentre are (2,3),(5,8), then the circumradiu is

In triangle ABC ,the equation of side BC is x-y=0. The circumcenter and orthocentre of triangle are (2,3) and (5,8), respectively. The equation of the circumcirle of the triangle is x^(2)+y^(2)-4x+6y-27=0x^(2)+y^(2)-4x-6y-27=0x^(2)+y^(2)+4x+6y-27=0x^(2)+y^(2)+4x+6y-27=0

In a Delta ABC the equation of the side BC is 2x-y =3 and its circumcentre and orthocentre are (2,4) and (1,2) respectively . Circumradius of Delta ABC is

In a Delta ABC the equation of the side BC is 2x-y =3 and its circumcentre and orthocentre are (2,4) and (1,2) respectively . Circumradius of Delta ABC is

In a Delta ABC ,the equation of the side BC is ,2x-y=3 and its circumcentre and orthocentre are (3,5) and (2,3) respectively. If R is the circum radius of Delta ABC then [R^(2)] is equal to (where [.] denotes (G.I.F)

In Delta ABC, if a=5, A=30^@ , then the circumradius is

The equation to the side "BC" of " Delta ABC " is " x+5=0 " .If " (-3,2) " is the orthocentre and "(0,0)" is the circumcentre then radius of the circle is

The orhtcentre and the centroid of Delta ABC are (5,8) and (3,14/3) respectively. The equation of the side BC is x-y=0 , Given that the image of the orthocentre of a triangle with respect to any side lies on the circumcircle of that triangle, then the diameter of the circumcircle of Delta ABC is