Potential energy of a particle is related to x coordinate by equation `x^2 - 2x` . Particle will be in stable equilibrium at :

Potential energy of a particle at position x is given by U = (x^2 - 4x) J . Which of the following is equilibrium position of the particle?

Potential energy of a particle at position x is given by U = (x^2 - 4x) J . Which of the following is equilibrium position of the particle?

Potential energy of a particle at position x is given by U=x^(2)-5x . Which of the following is equilibrium position of the particle?

Potential energy of a particle at position x is given by U=x^(2)-5x . Which of the following is equilibrium position of the particle?

Potential energy of a particle varies with x according to the relation U(x)=x^(2)-4x .The point "x=2" is a point of

In the figure the variation of potential energy of a particle of mass m = 2kg is represented w.r.t. its x-coordinate. The particle moves under the effect of this conservative force along the x-axis. If the particle is released at the origin then

The potential energy of a particle varies with x according to the reltiaon U(x) =x^(2)-4x . The point x =2 is a point of

The potential energy of a particle under a conservative force is given by U ( x) = ( x^(2) -3x) J. The equilibrium position of the particle is at