" The circles "x^(2)+y^(2)+x+y=0" and "x^(2)+y^(2)+x-y=0" intersect at an angle of "

The circle x^2+y^2+x+y=0 and x^2+y^2+x-y=0 intersect at an angle of :

If the circles x ^(2) + y ^(2) + 5x -6y-1=0 and x ^(2) + y^(2) +ax -y +1=0 intersect orthogonally (the tangents at the point of intersection of the circles are at right angles), the value of a is

The two curves x^3 - 3x y^2 + 2 = 0 and 3x^2y - y^3 - 2 = 0 intersect at an angle of

The two circles x ^(2)+y^(2)-2x +22y +5=0 and x ^(2) + y^(2) +14 x+6y +k=0 intersect orthogonally provided k is equal to-

Show that the circles x^(2) + y^(2) + 6x + 2y + 8 = 0 and x^(2) + y^(2) + 2x + 6y + 1 = 0 intersect each other.

A circle passing through the intersection of the circles x ^(2) + y^(2) + 5x + 4=0 and x ^(2) + y ^(2) + 5y -4 =0 also passes through the origin. The centre of the circle is

The equation of the circle which passes through the points of intersection of the circleS x^(2)+y^(2)-6 x=0 and x^(2)+y^(2)-6 y=0 and has centre at ((3)/(2), \(3)/(2)) is