[" Locus of point of "],[" intersection of the lines "],[x sin theta-y cos theta=0" and "],[ax sec theta-by cos e theta=a^(2)-b^(2)]

Locus of point of intersection of the lines x sin theta-y cos theta=0 and ax sec theta-by cos ec theta=a^(2)-b^(2)

Locus of point of intersection of the lines x sin theta-y cos theta=0 and ax sec theta-by cos ec theta=a^(2)-b^(2)

Locus of point of intersection of the lines x sin theta-y cos theta=0 and ax sec theta-by "cosec"theta=a^(2)-b^(2) is

The locus of the point of intersection of the lines ax sec theta+by tan theta=a and ax tan theta+by sec theta=b is

The locus of the points of intersection of the lines x cos theta+y sin theta=a and x sin theta-y cos theta=b , ( theta= variable) is :

The locus of the points of intersection of the lines x cos theta+y sin theta=a and x sin theta-y cos theta=b , ( theta= variable) is :

Prove that for all values of theta ,the locus of the point of intersection of the lines x cos theta+y sin theta=a and x sin theta-y cos theta=b is a circle.

For different values of theta, the locus of the point of intersection of the straight lines x sin theta-y(cos theta-1)=a sin theta and x sin theta-y(cos theta+1)+a sin theta=0 represents

The equation of the locus of the point of intersection of the straight lines x sin theta + (1- cos theta) y = a sin theta and x sin theta -(1+ cos theta) y + a sin theta =0 is:

The locus of the point of intersection of the lines x sin theta+(1-cos theta)y=a sin theta and x sin theta -(1+cos theta )y+a sin theta =0 is