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If tantheta=a/b , then (asintheta+bcosth...

If `tantheta=a/b` , then `(asintheta+bcostheta)/(asintheta-bcostheta)` is equal to (a) `(a^2+b^2)/(a^2-b^2)` (b) `(a^2-b^2)/(a^2+b^2)` (c) `(a+b)/(a-b)` (d) `(a-b)/(a+b)`

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