Two particles are released from the same height at an interval of `1s`. How long aftger the first particle begins to fall will the two particles be `10m` apart? (`g=10m//s^(2)`)

Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g = 10 m//s^2.

Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g = 10 m//s^2.

Two bodies begin a free fall from rest from the same height 2 seconds apart. How long after the first body begins to fall, the two bodies will be 40 m apart? ("Take g = 10ms"^(-2))

Two bodies begin a free fall from rest from the same height 2 seconds apart. How long after the first body begins to fall, the two bodies will be 40 m apart? ("Take g = 10ms"^(-2)) 1 s 2 s 3 s 4 s

Two balls are released from the same height at an interval of 2s. When will the separation between the balls be 20m after the first ball is released? Take g=10m//s^(2) .

Two particles begin to fall freely from the same height but the second falls t_(0) second after the first. Find the time (after the dropping of first) when separation between the particles is h_(0) .

A particle is thrown vertically up from the top of a building of height 20m with initial velocity u. A second particle is released from the same point 1 second later. If both particles reach the ground at the same instant , 3u = m//s. [Take g= 10m//s^(2) ]

A particle is thrown vertically up from the top of a building of height 20m with initial velocity u. A second particle is released from the same point 1 second later. If both particles reach the ground at the same instant , 3u = m//s. [Take g= 10m//s^(2) ]

A particle is relased from a height 20 m from the ground . After how much time and with what speed the particle hits time and with what speed the particle hits the ground ? [ "Take ": g=10 m* s^(-2)]