Home
Class 11
PHYSICS
A bob of mass 2 kg hangs from a string ...

A bob of mass 2 kg hangs from a string of length 5 m . It swings from its rest position to one of the sides so that the string makes an angle of `60^(@)` with the vertical Calculate the gain in potential energy of the bob .

Text Solution

AI Generated Solution

To solve the problem of calculating the gain in potential energy of a bob swinging from a vertical position, we can follow these steps: ### Step 1: Understand the Physical Situation We have a bob of mass \( m = 2 \, \text{kg} \) hanging from a string of length \( L = 5 \, \text{m} \). The bob swings to one side, making an angle of \( 60^\circ \) with the vertical. ### Step 2: Determine the Height Change When the bob swings to the side, it rises to a certain height. To find this height, we can use trigonometry. ...
Promotional Banner

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS|27 Videos
  • WORK, ENERGY AND POWER

    MODERN PUBLICATION|Exercise Conceptual Questions|20 Videos
  • WAVES

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|14 Videos

Similar Questions

Explore conceptually related problems

A girl of mass 40 kg sits in a swing formed by a rope of 6 m length. A person pulls the swing to a side so that the rope makies an angle of 60^(@) with the vertical. What is the gain in potential energy of the girl ?

The mass of a simple pendulum bob is 100 gm. The length of the pendulum is 1 m. The bob is drawn aside from the equilibrium position so that the string makes an angle of 60^(@) with the vertical and let go. The kinetic energy of the bob while crossing its equilibrium position will be

A girl of mass 40kg sits on a swing formed by a rope 6m long. A person pulls the swing to a side so that the rope makes an angle of 60^(@) with vertical . What is the gain in P.E. of the girl.

A body of mass m hangs at one end of a string of length l , the other end of which is fixed. It is given a horizontal velocity so that the string would just reach where it makes an angle of 60^(@) with the vertical. The tension in the string at mean position is

A nail is located at a certain distance vertically below the point of suspension of a simple pendulum. The pendulum bob is released from a position where the string makes an angle of 60^(@) with the vertical. Calculate the distance of nail from the point of suspension such that the bob will just perform revolutions with the nail as centre. Assume the length of the pendulum to be one meter.

Consider a simple pendulam of length 1 m. Its bob performs a circular motion is horizontal plane with its string making an angle 60^@ with the vertical. The centripetal accleration experienced by the bob is

A small bob is suspended from the roof with a string and hangs vertically. The bob is given a charge +q and a uniform horizontal electric field is set up o the neighbourhood of the bob. Now the bob hangs intjhe field such that the string makes an angle of 30^(@) with the vertical. If the charge on te bob is made +3q, and the bob once again comes to equilibrium, then the angle made by the string with the vertical will be

A bob is suspended from an ideal string makes an angle 60^(@) to the verticle and whirled along a horizontal circle.Then its perod of revolution is

A simple pendulum is constructed by attaching a bob of mas m to a string of length L fixed at its upper end. The bob oscillates in a vertical circle. It is found that the speed of the bob is v when the string makes an angle theta with the vertical. Find the tension in the string at this instant.

A bob of mass 1 kg is suspended from an inextensible string of length 1 m. When the string makes an angle 60^(@) with vertical, speed of the bob is 4 m/s Net acceleration of the bob at this instant is