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A bob of mass 0.3 kg falls from the ceil...

A bob of mass 0.3 kg falls from the ceiling of an elevator moving down with a uniform speed of `7ms^(-1)`. If hits the floor of the elevator (length of the elevator `=` 3m) and does not rebound. What is the heat produced by the impact ? Would your answer be different if the elevator were stationary ?

Text Solution

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Mass of the bolt = m = 0.3 kg
Length of the elevator = h = 3m
speed of the elevator = `7 " m "s^(-1)`
As the elevator is moving down with uniform speed therefore the value of g remains same .
As the bolt does not rebound on hitting the floor of the elevator , therefore , all the potential energy will be changed into the heat energy .
Heat produced = mgh
or `H = 0.3 xx9.8 xx3 = 8.82 J `
Heat produced will be the same independent of whether the elevator is moving or not . So , if the elevator were stationary even then the heat produced will bee equal to 8.82 J
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