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An adult weighing 600N raises the centre...

An adult weighing 600N raises the centre of gravity of his body by 0.25m while taking each step of 1m lenth in jogging. If he jogs for 6km, calculate the energy utilised by him in jogging assuming that there is no energy loss dur to friction of ground and air. Assuming that the body of the adult is capable of converting `10%` of energy intake in the form of food, calculate the energy equivalent fo food that would be required to compensate energy utilised for jogging.

Text Solution

Verified by Experts

Given mg = 600 N , h = 0.25 m per step
If length of each is 1 m , then in 6 km there are 6000 steps is 1 m , then in 6 km there are 600 steps
` . " " E = 6000 (mg) h `
` = 6000 xx 600 0.25 `
` = 9 xx 10^(5) J `
This is 10 % if intake energy .
` :. ` Intake energy = `10 E = 9 xx 10^(6) J `
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