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What is the minimum energy released in t...

What is the minimum energy released in the annhilation of an electron positron pair?

A

1.02 eV

B

1.02 MeV

C

2.04 MeV

D

931.2 MeV

Text Solution

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The correct Answer is:
B
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Calculate the amount of energy set free by the annigilation of an electron and a positron. Given that mass of electron = 0.00055 amu and positron = 0.00055 amu.

In an accelerator experiment on high energy collision of electrons with positrons, a certain events is interpted as annhilation of an electron-positron pair of total energy 10.2 BeV into two gamma -rays of equal energy. What is the wavelength associated with each gamma -rays? (1BeV=10^(9)eV)

Knowledge Check

  • The miniumum amount of energy released in annihilation of electron-Positron is

    A
    `1.02 MeV`
    B
    `0.58 MeV`
    C
    `185 MeV`
    D
    `200 MeV`
  • The amount of energy released on the addition of an electron in outermost shell of an atom is called:

    A
    ionization enthalpy
    B
    Hydration enthalpy
    C
    Electronegativity
    D
    electron gain enthalpy
  • The minimum energy required to remove an electron is called

    A
    Stoping potential
    B
    Kinetic energy
    C
    Work function
    D
    None of these
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