If the momentum of a body is increased by 50%, then the percentage increase in its kinetic energy is

Explanation

Intial momentum = P
Increase in mometum = `50/100 P = P/2 `
Final momentum ` = P + P/2 = 3/2 P `
Initial K.E ` = (P^(2))/(2m) = E `
E. = Final K.E = `((3/2P)^(2))/(2m)`
` 9/4 (P^(2))/(2m) = 9/4 E `
Increase in K.E = E. - E
` = 9/4 E - E = (5E)/4`
% increase in K.E = `(E.-E)/E xx100`
`= (5E)/(4.E) xx100 = 125 % `