A block of mass `m` at rest is acted upon by a force `F` for a time t. The kinetic energy of block after time t is

Options

A. `(P^(2)t^(2))/(m)`
B. `(P^(2)t^(2))/(2m)`
C. `(P^(2)T^(2))/(3m)`
D. `(Pt)/(2m)`

Answer

B

Explanation

Given , P = ma
E = kinetic energy ` = 1/2 mv^(2)`
`v = at`
`E = 1/(2m) (m^(2)a^(2))t^(2) = 1/(2m) P^(2)t^(2)`
` (P^(2)t^(2))/(2m)`