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A toy gun a spring of force constant k. ...

A toy gun a spring of force constant `k`. When changed before being triggered in the upward direction, the spring is compressed by a distance `x`. If the mass of the shot is `m`, on the being triggered it will go up to a height of

A

`(2mg)/(kx^(2))`

B

`(kx^(2))/(mg)`

C

`(kx)/(mg)`

D

`(kx^(2))/(2mg)`

Text Solution

Verified by Experts

The correct Answer is:
D

Stored potential energy in gun spring pushes the shot up to height .h. and shot acquires gravitational potential energy .
`1/2 kx^(2) =mgh`
`h = (kx^(2))/(2mg)`
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