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A body of mass 1 kg is thrown upwards wi...

A body of mass `1 kg` is thrown upwards with a velocity `20 ms^(-1)`. It momentarily comes to rest after attaining a height of `18 m`. How much energy is lost due to air friction? `(g = 10 ms^(-2))`

A

30 J

B

40 J

C

10 J

D

20 J

Text Solution

Verified by Experts

The correct Answer is:
D

Kinetic energy = P.E + energy consumed by air friction .
Loss in energy to air friction ` = 1/2mv^(2) -mgh`
`= 400/2 - 180 =20 J `
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