If the potential energy of a spring is V on stretching it by `2 cm`, then its potential energy when it is stretched by `10 cm` will be

Options

A. `U/25`
B. `U/5`
C. 25 U
D. 5 U

Answer

C

Explanation

`U=1/2K (2/100)^(2) = 1/2 xxKxx4xx10^(-4)`
`U. = 1/2K (10/100)^(2) = 1/2 K xx100 xx10^(-4)`
`=(100)/4 (1/2K xx 4 xx10^(-4))`
U. = 25(U)