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The block of mass M moving on the frict...

The block of mass `M` moving on the frictionless horizontal surface collides with the spring constant `k` and compresses it by length `L` . The maximum momention of the block after collision is

A

`sqrt(MK)` L

B

`(KL^(2))/(2M)`

C

zero

D

`(ML^(2))/K `

Text Solution

Verified by Experts

The correct Answer is:
A

Potential energy stored in spring due to compression is equal to the kinetic energy of the block .
`1/2 KL^(2)=(P^(2))/(2M)`
`P = sqrt(MK)` L
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