A block of mass 0.50 kg is moving with a speed of 2.00 m/s on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Options

A. 0.16 J
B. 1.00 J
C. 0.67 J
D. 0.34 J

Answer

C

Explanation

Linear momentum is conserved
`m_(1)u_(1)+m_(2)u_(2) = (m_(1)+m_(2)) v `
`v = 2/3 ` m/s
Loss in kinetic energy = `1/2 (0.5)xx(2)^(2) -1/2(1.5) xx(2/3)^(2)`
=0.67 J
(This energy migt be converted into sound energy or heat energy ) .