A mass m moves with a velocity v and collides inelastically with another identical mass. After collision the 1st mass moves with velocity `v/(sqrt3)` in a direction perpendicular to the initial direction of motion. Find the speed of the second mass after collision

Options

A. v
B. `sqrt(3)`v
C. `(2v)/(sqrt(3))`
D. `v/(sqrt(3))`

Answer

B

Explanation

Conservation of linear momentum along X-axis
`mv-mv_(1) cos theta `
`v = v_(1) cos theta " " …(i)`

Conservation f linear momentum along Y - axis ,
`0 = (mv)/(sqrt(3)) = mv_(1)sin theta `
`v/(sqrt(3)) = v_(1) sin theta `
From equaton (i)
`(v^(2))/(3) = v_(1)^(2)(1-cos^(2)theta) = (v_(1)^(2)-v^(2))`

` :. " " v_(1) = 2/(sqrt(3)) v `