Home
Class 11
PHYSICS
The distance x of a particle moving in o...

The distance x of a particle moving in one dimensions, under the action of a constant force is related to time t by the equation, `t=sqrt(x)+3`, where x is in metres and t in seconds. Find the displacement of the particle when its velocity is zero.

A

0 m

B

2 m

C

4 m

D

6 m

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    MODERN PUBLICATION|Exercise Objective Type Questions (Assertion Reason Type Questions)|13 Videos

  • WORK, ENERGY AND POWER

    MODERN PUBLICATION|Exercise Objective Type Questions (Matrix Match Type Questions)|2 Videos

  • WORK, ENERGY AND POWER

    MODERN PUBLICATION|Exercise Objective Type Questions (C. Multiple Choice Questions)|16 Videos

  • WAVES

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|14 Videos

Similar Questions

Explore conceptually related problems

The displacement x of a particle moving in one dimension under the action of a constant force is related to time t by the equation t=sqrt(x)+3 , where x is in meter and t is in second. Find the displacement of the particle when its velocity is zero.

The displacement x of a particle moving in one dismension under the action of a constant force is frlated to time t by the equation tsqrtx+3 , where x is in merers and t is in seconds, Find the displacemect of the particle when its velocity is zero.

The displacement x of particle moving in one dimension, under the action of a constant force is related to the time t by the equation t = sqrt(x) +3 where x is in meters and t in seconds . Find (i) The displacement of the particle when its velocity is zero , and (ii) The work done by the force in the first 6 seconds .

The distance (x) particle moving in one dismension, under the action of a constant force is related to time (t) by equation tsqrt x +3 where (x) is in vettres and (t) in seconds. Find the displacement of the particle when its velcity is zero.

The displacement x of a particle of mass 1.0 kg moving the one dimension under the action of a force is related to time t by the equation t=sqrt(x)+5 where x is in meter and t is in second. The magnitude of the momentum of the particle

The displacement x of a particle of mass m kg moving in one dimension, under the action of a force, is related to the time t by the equation t=4x+3 where x is in meters and t is in seconds. The work done by the force in the first six seconds in joules is

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force is released to time 't' (in sec) by t = sqrt(x) + 3 . The displacement of the particle when its velocity is zero will be.

The motion of a particle along a straight line is described by equation : x = 8 + 12 t - t^3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is.

Knowledge Check

  • The displacement x of a particle moving in one dismension under the action of a constant force is frlated to time t by the equation tsqrtx+3 , where x is in merers and t is in seconds, Find the displacemect of the particle when its velocity is zero.

    A
    Zero
    B
    `12 m`
    C
    ` 6 m`
    D
    ` 18 m`

  • The displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t=sqrt(3)+3 , where x is in meters and t is in seconds. The work done by the force in the first 6 seconds is

    A
    9 J
    B
    6 J
    C
    0 J
    D
    3 J

  • The displacement x of a particle of mass 1.0 kg moving the one dimension under the action of a force is related to time t by the equation t=sqrt(x)+5 where x is in meter and t is in second. The magnitude of the momentum of the particle

    A
    remains constant
    B
    increases with time
    C
    first decreases the then increases with time
    D
    decreases with time