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A ball of mass 0.1 kg is thrown verti...

A ball of mass 0.1 kg is thrown vertically with a speed of ` 7 " m "s^(-1)` . Calculate the kinetic energies after half second .

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m=0.1 kg, `u = 7 " m s"^(-1)`
` a = - g = - 9.8 ms^(-1) , t = 1/2 s`
Kinetic energy = `1/2 mv^(2)`
`v = u +at`
`= 7 - 9.8 xx1/2 = 2.1 " m s"^(-1)`
K.E ` = 1/2 mv^(2) = 1/2 xx0.1 xx(2.1)^(2)JB = 0.22 J `
` = 3.5 - 1.22 = 2.28 m `
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