Calculate the critical angle for a liquid in which speed of light is `1.2 xx 10^(8) m//s` assuming that a ray of light passes from this liquid into air.

Explanation

To calculate the critical angle for a liquid where the speed of light is given as \(1.2 \times 10^8 \, \text{m/s}\), we can follow these steps:

### Step 1: Determine the speed of light in vacuum
The speed of light in vacuum (\(c\)) is approximately:
\[ c = 3.0 \times 10^8 \, \text{m/s} \]

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