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A point source of light is placed in air...

A point source of light is placed in air, 100 cm away from a convex spherical surface, made of material of refractive index 1.5 and having radius of curvature = 20 cm. If the source emits light, at what position from the convex surface image will be formed?

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To find the position of the image formed by the convex spherical surface, we can use the formula for refraction at a spherical surface: \[ \frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R} \] Where: - \( \mu_2 \) = refractive index of the medium where the image is formed (1.5 for the convex surface) ...
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(i) Device the mathematical n between refractive indices n_(1) and n_(2) of two radii and radius of curvature R for refraction at a convex shperical surface. Consider the object to be a point since lying on the principal axis in rarer medium of refractive index n_(1) and a real image formed in the denser medium of refractive index n_(2) . Hence, derive lens marker's formula. (ii) Light from a point source in air falls on a convex spherical glass surface of refractive index 1.5 and radius of curvature 20cm . The distance of light source from the glass surface is 100cm . At what position is the image formed ?