A convex lens of material of refractive index 1.5 is immersed in a liquid of refractive index (i) 1.3 (ii) 1.6 and (iii) 1.5. What will happen to the focal length and nature of lens in all three cases?

Explanation

To solve the problem, we will analyze the behavior of a convex lens with a refractive index of 1.5 when it is immersed in three different liquids with refractive indices of 1.3, 1.6, and 1.5. We will use the lensmaker's formula to determine the focal length and nature of the lens in each case.

### Step-by-Step Solution

1. **Understanding the Lensmaker's Formula**:
The lensmaker's formula is given by:
\[
\frac{1}{f} = \left(\frac{\mu_l}{\mu_m} - 1\right) \left(\frac{1}{r_1} - \frac{1}{r_2}\right)
...