A thin convex lens made of glass of refractive index `3//2` has a power of 5 D. When it is immersed in a liquid of refractive index `mu`, it behaves like a divergent lens of focal length 1 m. Calculate the refractive index of the liquid.

Explanation

To solve the problem, we will use the lens maker's formula and the relationship between power and focal length. Let's break it down step by step.

### Step 1: Understand the given information
- The refractive index of the glass lens, \( \mu_1 = \frac{3}{2} = 1.5 \).
- The power of the lens, \( P = 5 \, D \).
- The focal length when in air, \( f_1 \).
- The lens behaves like a divergent lens when immersed in a liquid of refractive index \( \mu \), with a focal length \( f_2 = -1 \, m \).

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