A magnifying glass is rated 6X for a normal relaxed eye. For a relaxed farsighted eye whose near point is 50 cm, then what will be its magnifying power?

Explanation

To solve the problem, we need to determine the magnifying power of a magnifying glass for a relaxed farsighted eye whose near point is 50 cm. We will use the formula for magnifying power (M) of a magnifying glass, which is given by:

\[ M = \frac{D}{f} \]

where:
- \( D \) is the near point distance for the eye (25 cm for a normal eye, 50 cm for the farsighted eye),
- \( f \) is the focal length of the lens.

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