A ray of light is incident at an angle of `60^(@)` on one face of a rectangular glass slab of thickness `0.1 m`, and refractive index `1.5`.Calculate the lateral shift produced.

Explanation

First of all we can calculate angle of refraction r in glass slab when angle of incident in air is `60^(@)`.
`mu sin theta="constant"`
`rArr" "1xxsin 60^(@)=1.5xxsinr`
`rArr" "sinr=0.5773`
`rArr" "r=35.26^(@)`
We know that lateral displacement is given by the following relation :
`delta=(tsin(i-r))/(cosr)`
`rArr" "delta=(0.1xxsin(60^(@)-35.26^(@)))/(cos35.26)`
`rArr" "delta=(0.1xxsin24.74^(@))/(cos35.26)`
`rArr" "delta=(0.1xx0.4185)/(0.8165)=0.0512m`