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The near point of a person having hyperm...

The near point of a person having hypermetropia is 60 cm in front of the eye. Find the focal length and power of lens required to enable him to see the objects clearly placed at 25 cm from the eye.

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To solve the problem of finding the focal length and power of the lens required for a person with hypermetropia, we can follow these steps: ### Step 1: Understand the Problem The person has a near point of 60 cm, which means they can only see objects clearly that are at least 60 cm away. We need to help them see an object that is placed at 25 cm. ### Step 2: Define the Variables - The object distance (u) is given as -25 cm (the negative sign indicates that the object is on the same side as the incoming light). - The image distance (v) should be -60 cm (since the person can see clearly only at this distance). ...
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MODERN PUBLICATION-RAY OPTICS AND OPTICAL INSTRUMENTS-Revision Exercises (Numerical Problems)
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  15. Calculate the dispersive power of flint glass if deviations produced b...

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  16. The far point of a person having myopia is 200 cm in front of the eye....

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  17. The near point of a person having hypermetropia is 60 cm in front of t...

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  18. Being myopic, the far point for the left eye of a person has shifted t...

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  20. If a convex lens of focal length 20 cm is held close to the eye of obs...

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