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There is a symmetric bi-convex lens and ...

There is a symmetric bi-convex lens and it is cut in two equal parts by a plane passing through the centre of lens and perpendicular to its principal axis. If power of original lens is 10 D then what will be the power of each part of the lens ?

A

10 D

B

20 D

C

5 D

D

2.5 D

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the power of each half of a symmetric bi-convex lens after it has been cut into two equal parts. The original lens has a power of 10 diopters. ### Step-by-Step Solution: 1. **Understanding the Power of the Lens**: The power \( P \) of a lens is given by the formula: \[ P = \frac{1}{f} \] where \( f \) is the focal length of the lens in meters. Given that the power of the original lens is 10 D, we can find the focal length: \[ P = 10 \, \text{D} \implies f = \frac{1}{P} = \frac{1}{10} = 0.1 \, \text{m} \] 2. **Cutting the Lens**: When the symmetric bi-convex lens is cut into two equal halves by a plane passing through the center and perpendicular to the principal axis, each half will still retain the same curvature but will now act as a plano-convex lens. 3. **Calculating the New Power**: For each half of the lens, the new configuration can be analyzed. The focal length of a plano-convex lens can be derived from the lens maker's formula: \[ \frac{1}{f} = (n - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \] Here, for the plano-convex lens: - \( R_1 = R \) (the radius of curvature of the convex side) - \( R_2 = \infty \) (the flat side) Therefore, the formula simplifies to: \[ \frac{1}{f} = (n - 1) \left( \frac{1}{R} - 0 \right) = (n - 1) \frac{1}{R} \] 4. **Using the Original Lens Power**: For the original lens: \[ \frac{1}{f} = (n - 1) \left( \frac{2}{R} \right) = 10 \] This means: \[ n - 1 = \frac{10R}{2} = 5R \] 5. **Finding the Power of Each Half**: Now, substituting \( n - 1 \) back into the formula for the half-lens: \[ \frac{1}{f'} = (n - 1) \frac{1}{R} = 5R \cdot \frac{1}{R} = 5 \] Thus, the power of each half-lens is: \[ P' = \frac{1}{f'} = 5 \, \text{D} \] ### Final Answer: The power of each part of the lens after cutting is **5 diopters**.

To solve the problem, we need to determine the power of each half of a symmetric bi-convex lens after it has been cut into two equal parts. The original lens has a power of 10 diopters. ### Step-by-Step Solution: 1. **Understanding the Power of the Lens**: The power \( P \) of a lens is given by the formula: \[ P = \frac{1}{f} ...
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